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Popular >

derivative of ln(10x^2-8)

Solution

\frac{d}{d x} (ln (10 x^{2} - 8))

Solution

\frac{10 x}{5 x ^{2} - 4}

Solution steps

\frac{d}{d x} (ln (10 x^{2} - 8))

Apply the chain rule:

\frac{1}{10 x ^{2} - 8} \frac{d}{d x} (10 x^{2} - 8)

= \frac{1}{10 x ^{2} - 8} \frac{d}{d x} (10 x^{2} - 8)

\frac{d}{d x} (10 x^{2} - 8) = 20 x

= \frac{1}{10 x ^{2} - 8} \cdot 20 x

Simplify

\frac{1}{10 x ^{2} - 8} \cdot 20 x : \frac{10 x}{5 x ^{2} - 4}

= \frac{10 x}{5 x ^{2} - 4}

Popular Examples

y^'=e^{2t+y-1}-2

y^{^{'}} = e^{2 t + y - 1} - 2

(\partial)/(\partial x)(e^{xy}+ln(x/y))

\frac{\partial}{\partial x} (e^{x y} + ln (\frac{x}{y}))

(\partial)/(\partial x)(2xy^2+4)

\frac{\partial}{\partial x} (2 x y^{2} + 4)

limit as w approaches infinity of (2w^2-3w+4)/(5w^2+7w-1)

w \to \infty lim (\frac{2 w ^{2} - 3 w + 4}{5 w ^{2} + 7 w - 1})

y^{^{''}} - k y = 0

Frequently Asked Questions (FAQ)

What is the derivative of ln(10x^2-8) ?
The derivative of ln(10x^2-8) is (10x)/(5x^2-4)
What is the first derivative of ln(10x^2-8) ?
The first derivative of ln(10x^2-8) is (10x)/(5x^2-4)