What is the derivative of y=sqrt(4-x) ?

The derivative of y=sqrt(4-x) is -1/(2sqrt(4-x))

What is the first derivative of y=sqrt(4-x) ?

The first derivative of y=sqrt(4-x) is -1/(2sqrt(4-x))

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derivative of

y = 4 - x

- \frac{1}{2 4 - x}

Solution steps

\frac{d}{d x} (4 - x)

Apply the chain rule:

\frac{1}{2 4 - x} \frac{d}{d x} (4 - x)

= \frac{1}{2 4 - x} \frac{d}{d x} (4 - x)

\frac{d}{d x} (4 - x) = - 1

= \frac{1}{2 4 - x} (- 1)

Simplify

= - \frac{1}{2 4 - x}

\frac{d}{d x} (10 x lo g_{10} (100 x))

ln (y)

y = x^{2} sin^{7} (x) + x cos^{- 6} (x)

\int \frac{1}{- 20 x - 20 x} d x

x y^{^{'}} + (1 + 2 x^{2}) y = x^{3} e^{- x^{2}}

What is the derivative of y=sqrt(4-x) ?
The derivative of y=sqrt(4-x) is -1/(2sqrt(4-x))
What is the first derivative of y=sqrt(4-x) ?
The first derivative of y=sqrt(4-x) is -1/(2sqrt(4-x))