What is the tangent of f(x)=-3x^3-2x^2-x+3,(-,5) ?

The tangent of f(x)=-3x^3-2x^2-x+3,(-,5) is y=-6.61329…x+11.61329…

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tangent of f(x)=-3x^3-2x^2-x+3,(-,5)

tangent of

f (x) = - 3 x^{3} - 2 x^{2} - x + 3, (-, 5)

y = - 6.61329 \dots x + 11.61329 \dots

Solution steps

Slope of the tangent line at

(-, 5) : m = \frac{- 3 x ^{3} - 2 x ^{2} - x - 2}{x}

Find the slope of

f (x) = - 3 x^{3} - 2 x^{2} - x + 3 : m = - 9 x^{2} - 4 x - 1

Solve

- 9 x^{2} - 4 x - 1 = \frac{- 3 x ^{3} - 2 x ^{2} - x - 2}{x} : x \approx 0.59819 \dots

Find the tangent line at

x = 0.59819 \dots : y = - 6.61329 \dots x + 11.61329 \dots

y = - 6.61329 \dots x + 11.61329 \dots

n = 1 \sum \infty \frac{1}{n ^{7}}

\int sin (12 x) cos (9 x) d x

x \to 0 + lim (arctan (\frac{1}{x}))

\int_{- 2}^{0} (u^{5} - u^{3} + u^{2}) d u

\int_{1}^{2} 2 r^{4} ln (r) d r

What is the tangent of f(x)=-3x^3-2x^2-x+3,(-,5) ?
The tangent of f(x)=-3x^3-2x^2-x+3,(-,5) is y=-6.61329…x+11.61329…