What is the limit as x approaches infinity of-(sin^2(x)+2)/(2x-5) ?

The limit as x approaches infinity of-(sin^2(x)+2)/(2x-5) is 0

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limit as x approaches infinity of-(sin^2(x)+2)/(2x-5)

x \to \infty lim (- \frac{sin ^{2} ( x ) + 2}{2 x - 5})

0

Solution steps

x \to \infty lim (- \frac{sin ^{2} ( x ) + 2}{2 x - 5})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (\frac{sin ^{2} ( x ) + 2}{2 x - 5})

Apply the Squeeze Theorem:

0

= - 0

Simplify

= 0

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What is the limit as x approaches infinity of-(sin^2(x)+2)/(2x-5) ?
The limit as x approaches infinity of-(sin^2(x)+2)/(2x-5) is 0