What is the limit as x approaches 1+of 1/(ln(x)) ?

The limit as x approaches 1+of 1/(ln(x)) is infinity

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limit as x approaches 1+of 1/(ln(x))

x \to 1 + lim (\frac{1}{ln ( x )})

\infty

Solution steps

x \to 1 + lim (\frac{1}{ln ( x )})

For

x

approaching

1

from the right

, x > 1 \Rightarrow ln (x) > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int x sin (5 x^{2}) cos (8 x^{2}) d x

f (x) = 5 - \frac{4}{x}, (- 1, 1)

\int x^{9} e^{x^{10} - 9} d x

\int 2 e^{2 x + 5} d x

n = 1 \sum \infty arctan (3 n)

What is the limit as x approaches 1+of 1/(ln(x)) ?
The limit as x approaches 1+of 1/(ln(x)) is infinity