What is area f(x)=x^2-4,x=-4,x=3 ?

The answer to area f(x)=x^2-4,x=-4,x=3 is 71/3

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area f(x)=x^2-4,x=-4,x=3

area

f (x) = x^{2} - 4, x = - 4, x = 3

\frac{71}{3}

Decimal Notation

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

\int \frac{1}{x ^{2} a ^{2} - x ^{2}} d x

x \to - 3 lim (∣ x ∣ - 2)

e^{t}

f (x) = \frac{5 x}{x + 3}, 2, at x = 2

\frac{d}{d x} (2^{a r c t a n (x)})

What is area f(x)=x^2-4,x=-4,x=3 ?
The answer to area f(x)=x^2-4,x=-4,x=3 is 71/3