What is the solution for (dy)/(dx)=e^ycos(2x) ?

The solution for (dy)/(dx)=e^ycos(2x) is y=-ln(-1/2 sin(2x)-c_{1})

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(dy)/(dx)=e^ycos(2x)

\frac{d y}{d x} = e^{y} cos (2 x)

y = - ln (- \frac{1}{2} sin (2 x) - c_{1})

Solution steps

\frac{d y}{d x} = e^{y} cos (2 x)

Solve separable ODE:

y = - ln (- \frac{1}{2} sin (2 x) - c_{1})

y = - ln (- \frac{1}{2} sin (2 x) - c_{1})

f (t) = 2 cos (t)

x = - 2, x = 1, y = 3 x, y = x^{2} - 4

y^{^{''}} + y = 5 csc^{2} (t)

f (x) = 8 x^{10} + 6 x^{6}

\int \frac{1}{x ^{2}} e^{\frac{1}{x}} d x

What is the solution for (dy)/(dx)=e^ycos(2x) ?
The solution for (dy)/(dx)=e^ycos(2x) is y=-ln(-1/2 sin(2x)-c_{1})