What is the derivative of 2sin(x+sin(2x)) ?

The derivative of 2sin(x+sin(2x)) is 2cos(x)+cos(2x)*2

What is the first derivative of 2sin(x+sin(2x)) ?

The first derivative of 2sin(x+sin(2x)) is 2cos(x)+cos(2x)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 sin (x) + sin (2 x))

2 cos (x) + cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (2 sin (x) + sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) + \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= 2 cos (x) + cos (2 x) \cdot 2

\int \frac{15}{15 + e ^{x}} d x

\int_{0}^{100} \frac{1}{x} d x

\int_{0}^{1} 2 x d x

y = 4^{x + 1}

6 \cdot y^{^{''}} + 2 \cdot y^{^{'}} = 0, y^{^{'}} (0) = 4

What is the derivative of 2sin(x+sin(2x)) ?
The derivative of 2sin(x+sin(2x)) is 2cos(x)+cos(2x)*2
What is the first derivative of 2sin(x+sin(2x)) ?
The first derivative of 2sin(x+sin(2x)) is 2cos(x)+cos(2x)*2