What is the derivative of sqrt(2x)+\sqrt[3]{3x} ?

The derivative of sqrt(2x)+\sqrt[3]{3x} is 1/(sqrt(2)\sqrt{x)}+1/(3^{2/3)x^{2/3}}

What is the first derivative of sqrt(2x)+\sqrt[3]{3x} ?

The first derivative of sqrt(2x)+\sqrt[3]{3x} is 1/(sqrt(2)\sqrt{x)}+1/(3^{2/3)x^{2/3}}

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\frac{1}{2 x} + \frac{1}{3 ^{\frac{2}{3}} x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{1}{3 ^{\frac{2}{3}} x ^{\frac{2}{3}}}

\frac{\partial}{\partial x} (x^{2} + 1)

f (x) = 2 x e^{x} cos (x), at x = 0

\int_{0}^{2} sin (x) + e^{x} d x

\frac{d}{d x} ((\frac{1}{x})^{\frac{1}{2}})

What is the derivative of sqrt(2x)+\sqrt[3]{3x} ?
The derivative of sqrt(2x)+\sqrt[3]{3x} is 1/(sqrt(2)\sqrt{x)}+1/(3^{2/3)x^{2/3}}
What is the first derivative of sqrt(2x)+\sqrt[3]{3x} ?
The first derivative of sqrt(2x)+\sqrt[3]{3x} is 1/(sqrt(2)\sqrt{x)}+1/(3^{2/3)x^{2/3}}