What is the integral of 6t^2\sqrt[3]{t} ?

The integral of 6t^2\sqrt[3]{t} is 6(1/3 t^3\sqrt[3]{t}-1/30 t^{10/3})+C

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integral of 6t^2\sqrt[3]{t}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

\int \frac{1}{9} t^{\frac{7}{3}} d t = \frac{1}{30} t^{\frac{10}{3}}

Add a constant to the solution

\int \frac{3}{4} - x^{2} d x

\frac{d}{d x} (x^{2} + 7 x)

\int \frac{2 x + 2}{x ^{2} + 1} d x

\int \frac{x ^{7} e ^{x} - 8 x ^{6}}{x ^{7}} d x

\frac{d}{d x} (lo g_{18} (x^{2} - 5 x))

What is the integral of 6t^2\sqrt[3]{t} ?
The integral of 6t^2\sqrt[3]{t} is 6(1/3 t^3\sqrt[3]{t}-1/30 t^{10/3})+C