What is the limit as x approaches 8 of (sqrt(7+\sqrt[3]{x)}-3)/(x-8) ?

The limit as x approaches 8 of (sqrt(7+\sqrt[3]{x)}-3)/(x-8) is 1/72

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limit as x approaches 8 of (sqrt(7+\sqrt[3]{x)}-3)/(x-8)

\frac{1}{72}

Decimal Notation

0.01388 \dots

Solution steps

Apply L'Hopital's Rule

Plug in the value

x = 8

Simplify

= \frac{1}{72}

\int 3 x^{2} - 2 y^{2} d x

\int \frac{x}{1 - 2 x} d x

x \to 1 lim (3 + f (x))

\int t^{2} e^{- 4 t} d t

\frac{d}{d x} (\frac{4 x}{7 x - 2})

What is the limit as x approaches 8 of (sqrt(7+\sqrt[3]{x)}-3)/(x-8) ?
The limit as x approaches 8 of (sqrt(7+\sqrt[3]{x)}-3)/(x-8) is 1/72