What is the integral of (arccos(x)) ?

The integral of (arccos(x)) is xarccos(x)-sqrt(1-x^2)+C

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integral of (arccos(x))

\int (arccos (x)) d x

x arccos (x) - 1 - x^{2} + C

Solution steps

\int arccos (x) d x

Apply Integration By Parts

: x arccos (x) - \int - \frac{x}{1 - x ^{2}} d x

= x arccos (x) - \int - \frac{x}{1 - x ^{2}} d x

\int - \frac{x}{1 - x ^{2}} d x = 1 - x^{2}

= x arccos (x) - 1 - x^{2}

Add a constant to the solution

= x arccos (x) - 1 - x^{2} + C

\frac{d}{d x} (x + x^{2})

\frac{1}{s ^{2}} \cdot \frac{3}{( s + 1 )}

\int \frac{2 x + 1}{( x ^{2} + 4 ) ^{2} ( x + 1 ) ^{3}} d x

\frac{d}{d x} (x^{7} cos (x))

\frac{u}{u ^{2} + 6}

What is the integral of (arccos(x)) ?
The integral of (arccos(x)) is xarccos(x)-sqrt(1-x^2)+C