What are the solutions to the equation 2x^2=5x ?

The solutions to the equation 2x^2=5x are x=0,x= 5/2

Find the zeros of 2x^2=5x

The zeros of 2x^2=5x are x=0,x= 5/2

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2 x^{2} = 5 x

x = 0, x = \frac{5}{2}

Decimal Notation

x = 0, x = 2.5

Solution steps

2 x^{2} = 5 x

Move

5 x

to the left side

2 x^{2} - 5 x = 0

Factor

2 x^{2} - 5 x : x (2 x - 5)

x (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 5 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{2}

3 x^{2} = 5 x

(\frac{2 x y ^{5}}{x ^{3} y})^{- 3}

3 x^{2} + 18 x + 24 = 0

3 x - 8 \geq \times + 4

5 x^{2} - 35 x + 60 = 0

What are the solutions to the equation 2x^2=5x ?
The solutions to the equation 2x^2=5x are x=0,x= 5/2
Find the zeros of 2x^2=5x
The zeros of 2x^2=5x are x=0,x= 5/2