What are the solutions to the equation x^2-3=38 ?

The solutions to the equation x^2-3=38 are x=sqrt(41),x=-sqrt(41)

Find the zeros of x^2-3=38

The zeros of x^2-3=38 are x=sqrt(41),x=-sqrt(41)

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x^{2} - 3 = 38

x = 41, x = - 41

Decimal Notation

x = 6.40312 \dots, x = - 6.40312 \dots

Solution steps

x^{2} - 3 = 38

Move

3

to the right side

x^{2} = 41

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 41, x = - 41

7 (9 + x) = 84

15 x^{2} - 17 x - 42

4 a^{- 3} b^{- 2}

\frac{x ^{2}}{x ^{2}}

x^{2} - x - 14 = 0

What are the solutions to the equation x^2-3=38 ?
The solutions to the equation x^2-3=38 are x=sqrt(41),x=-sqrt(41)
Find the zeros of x^2-3=38
The zeros of x^2-3=38 are x=sqrt(41),x=-sqrt(41)