What are the solutions to the equation 1/4 x^2+11=38 ?

The solutions to the equation 1/4 x^2+11=38 are x=6sqrt(3),x=-6sqrt(3)

Find the zeros of 1/4 x^2+11=38

The zeros of 1/4 x^2+11=38 are x=6sqrt(3),x=-6sqrt(3)

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\frac{1}{4} x^{2} + 11 = 38

x = 63, x = - 63

Decimal Notation

x = 10.39230 \dots, x = - 10.39230 \dots

Solution steps

\frac{1}{4} x^{2} + 11 = 38

Move

11

to the right side

\frac{1}{4} x^{2} = 27

Multiply both sides by

4

x^{2} = 108

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 108, x = - 108

108 = 63

- 108 = - 63

x = 63, x = - 63

(8 + 7 i) (8 - 7 i)

6 - 8 ∣ - 6 x ∣ = - 90

- \frac{3}{2} (4)

- 2 + \frac{π}{2}

x^{2} - 18 x + 17

What are the solutions to the equation 1/4 x^2+11=38 ?
The solutions to the equation 1/4 x^2+11=38 are x=6sqrt(3),x=-6sqrt(3)
Find the zeros of 1/4 x^2+11=38
The zeros of 1/4 x^2+11=38 are x=6sqrt(3),x=-6sqrt(3)