What are the solutions to the equation 3x^2-17x-28=0 ?

The solutions to the equation 3x^2-17x-28=0 are x=7,x=-4/3

Find the zeros of 3x^2-17x-28=0

The zeros of 3x^2-17x-28=0 are x=7,x=-4/3

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3 x^{2} - 17 x - 28 = 0

x = 7, x = - \frac{4}{3}

Decimal Notation

x = 7, x = - 1.33333 \dots

Solution steps

3 x^{2} - 17 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 3 ( - 28 )}{2 \cdot 3}

(- 17)^{2} - 4 \cdot 3 (- 28) = 25

x_{1, 2} = \frac{- ( - 17 ) \pm 25}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 25}{2 \cdot 3}, x_{2} = \frac{- ( - 17 ) - 25}{2 \cdot 3}

x = \frac{- ( - 17 ) + 25}{2 \cdot 3} : 7

x = \frac{- ( - 17 ) - 25}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 7, x = - \frac{4}{3}

3 (x + 2) = x + 4

a^{2} + 2 ab

3 k = \frac{- 5 k - 4}{6}

\frac{( 3 - 55 i )}{5 + 7 i}

- 6 x \leq 30

What are the solutions to the equation 3x^2-17x-28=0 ?
The solutions to the equation 3x^2-17x-28=0 are x=7,x=-4/3
Find the zeros of 3x^2-17x-28=0
The zeros of 3x^2-17x-28=0 are x=7,x=-4/3