What are the solutions to the equation -x^2+6x=-34 ?

The solutions to the equation -x^2+6x=-34 are x=3-sqrt(43),x=3+sqrt(43)

Find the zeros of -x^2+6x=-34

The zeros of -x^2+6x=-34 are x=3-sqrt(43),x=3+sqrt(43)

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- x^{2} + 6 x = - 34

x = 3 - 43, x = 3 + 43

Decimal Notation

x = - 3.55743 \dots, x = 9.55743 \dots

Solution steps

- x^{2} + 6 x = - 34

Move

34

to the left side

- x^{2} + 6 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 34}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 34 = 243

x_{1, 2} = \frac{- 6 \pm 2 43}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 43}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 43}{2 ( - 1 )}

x = \frac{- 6 + 2 43}{2 ( - 1 )} : 3 - 43

x = \frac{- 6 - 2 43}{2 ( - 1 )} : 3 + 43

The solutions to the quadratic equation are:

x = 3 - 43, x = 3 + 43

5 \cdot \frac{π}{2}

2400

\frac{3}{4} + \frac{m}{8}

\frac{1}{6} - \frac{7}{18} + \frac{5}{9}

3 t^{2} - 16 t + 26 > 0

What are the solutions to the equation -x^2+6x=-34 ?
The solutions to the equation -x^2+6x=-34 are x=3-sqrt(43),x=3+sqrt(43)
Find the zeros of -x^2+6x=-34
The zeros of -x^2+6x=-34 are x=3-sqrt(43),x=3+sqrt(43)