What are the solutions to the equation 2x^2+20x+6=0 ?

The solutions to the equation 2x^2+20x+6=0 are x=-5+sqrt(22),x=-5-sqrt(22)

Find the zeros of 2x^2+20x+6=0

The zeros of 2x^2+20x+6=0 are x=-5+sqrt(22),x=-5-sqrt(22)

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2 x^{2} + 20 x + 6 = 0

x = - 5 + 22, x = - 5 - 22

Decimal Notation

x = - 0.30958 \dots, x = - 9.69041 \dots

Solution steps

2 x^{2} + 20 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 6 = 422

x_{1, 2} = \frac{- 20 \pm 4 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 4 22}{2 \cdot 2}, x_{2} = \frac{- 20 - 4 22}{2 \cdot 2}

x = \frac{- 20 + 4 22}{2 \cdot 2} : - 5 + 22

x = \frac{- 20 - 4 22}{2 \cdot 2} : - 5 - 22

The solutions to the quadratic equation are:

x = - 5 + 22, x = - 5 - 22

u + 50 = 4

7 k^{2} - 6 k + 3 = 3

5 x^{2} - 5 x - 10

5^{∣ 4 x - 6 ∣} = 2 5^{3 x - 4}

x^{3} < 100 x

What are the solutions to the equation 2x^2+20x+6=0 ?
The solutions to the equation 2x^2+20x+6=0 are x=-5+sqrt(22),x=-5-sqrt(22)
Find the zeros of 2x^2+20x+6=0
The zeros of 2x^2+20x+6=0 are x=-5+sqrt(22),x=-5-sqrt(22)