What are the solutions to the equation 4x^2-7=21 ?

The solutions to the equation 4x^2-7=21 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 4x^2-7=21

The zeros of 4x^2-7=21 are x=sqrt(7),x=-sqrt(7)

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4 x^{2} - 7 = 21

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

4 x^{2} - 7 = 21

Move

7

to the right side

4 x^{2} = 28

Divide both sides by

4

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

500 (\frac{1}{4}) e^{- 16 (\frac{1}{4})^{2}}

\frac{15 - 5}{5}

- \frac{25}{12} + 6

f = 4^{(1 - 1)}

y^{2} + 2 y - 48

What are the solutions to the equation 4x^2-7=21 ?
The solutions to the equation 4x^2-7=21 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 4x^2-7=21
The zeros of 4x^2-7=21 are x=sqrt(7),x=-sqrt(7)