What are the solutions to the equation (r+4)^2=13 ?

The solutions to the equation (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4

Find the zeros of (r+4)^2=13

The zeros of (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4

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(r + 4)^{2} = 13

r = 13 - 4, r = - 13 - 4

Decimal Notation

r = - 0.39444 \dots, r = - 7.60555 \dots

Solution steps

(r + 4)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r + 4 = 13 : r = 13 - 4

Solve

r + 4 = - 13 : r = - 13 - 4

The solutions to the quadratic equation are:

r = 13 - 4, r = - 13 - 4

g^{4} + 24 g^{3} + 12 g^{2} + 4 g

(\frac{\frac{6}{5}}{\frac{3}{5}})^{5}

\frac{12}{6}

- 2 + - 18

4 (2 y - 1) - 2 (2 y) = 2

What are the solutions to the equation (r+4)^2=13 ?
The solutions to the equation (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4
Find the zeros of (r+4)^2=13
The zeros of (r+4)^2=13 are r=sqrt(13)-4,r=-sqrt(13)-4