What are the solutions to the equation 5x^2+x-6=0 ?

The solutions to the equation 5x^2+x-6=0 are x=1,x=-6/5

Find the zeros of 5x^2+x-6=0

The zeros of 5x^2+x-6=0 are x=1,x=-6/5

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5 x^{2} + x - 6 = 0

x = 1, x = - \frac{6}{5}

Decimal Notation

x = 1, x = - 1.2

Solution steps

5 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 6) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 5}, x_{2} = \frac{- 1 - 11}{2 \cdot 5}

x = \frac{- 1 + 11}{2 \cdot 5} : 1

x = \frac{- 1 - 11}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{6}{5}

\frac{- 2}{3}

x^{2} (x - 1) \leq 0

0. 5^{2} + 0. 5^{2}

\frac{2}{3} ∣ x + 5 ∣ - \frac{5}{3} = - 1

\frac{1}{( 93 + 4 ) ( 93 + 10 )} < 1 0^{- 4}

What are the solutions to the equation 5x^2+x-6=0 ?
The solutions to the equation 5x^2+x-6=0 are x=1,x=-6/5
Find the zeros of 5x^2+x-6=0
The zeros of 5x^2+x-6=0 are x=1,x=-6/5