What are the solutions to the equation 2x^2+16x-3=0 ?

The solutions to the equation 2x^2+16x-3=0 are x=(-8+sqrt(70))/2 ,x=-(8+sqrt(70))/2

Find the zeros of 2x^2+16x-3=0

The zeros of 2x^2+16x-3=0 are x=(-8+sqrt(70))/2 ,x=-(8+sqrt(70))/2

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2 x^{2} + 16 x - 3 = 0

x = \frac{- 8 + 70}{2}, x = - \frac{8 + 70}{2}

Decimal Notation

x = 0.18330 \dots, x = - 8.18330 \dots

Solution steps

2 x^{2} + 16 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 (- 3) = 270

x_{1, 2} = \frac{- 16 \pm 2 70}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 2 70}{2 \cdot 2}, x_{2} = \frac{- 16 - 2 70}{2 \cdot 2}

x = \frac{- 16 + 2 70}{2 \cdot 2} : \frac{- 8 + 70}{2}

x = \frac{- 16 - 2 70}{2 \cdot 2} : - \frac{8 + 70}{2}

The solutions to the quadratic equation are:

x = \frac{- 8 + 70}{2}, x = - \frac{8 + 70}{2}

- 3 x + 7 x = - 12

- 5 ∣ 4 + n ∣ < - 15

3 v^{2} - 10 v = 8

e^{iπ}

x^{2} + 6 x + 9 > 0

What are the solutions to the equation 2x^2+16x-3=0 ?
The solutions to the equation 2x^2+16x-3=0 are x=(-8+sqrt(70))/2 ,x=-(8+sqrt(70))/2
Find the zeros of 2x^2+16x-3=0
The zeros of 2x^2+16x-3=0 are x=(-8+sqrt(70))/2 ,x=-(8+sqrt(70))/2