What are the solutions to the equation 4x^2+31x=-42 ?

The solutions to the equation 4x^2+31x=-42 are x=-7/4 ,x=-6

Find the zeros of 4x^2+31x=-42

The zeros of 4x^2+31x=-42 are x=-7/4 ,x=-6

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4 x^{2} + 31 x = - 42

x = - \frac{7}{4}, x = - 6

Decimal Notation

x = - 1.75, x = - 6

Solution steps

4 x^{2} + 31 x = - 42

Move

42

to the left side

4 x^{2} + 31 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 4 \cdot 42}{2 \cdot 4}

3 1^{2} - 4 \cdot 4 \cdot 42 = 17

x_{1, 2} = \frac{- 31 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 31 + 17}{2 \cdot 4}, x_{2} = \frac{- 31 - 17}{2 \cdot 4}

x = \frac{- 31 + 17}{2 \cdot 4} : - \frac{7}{4}

x = \frac{- 31 - 17}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = - \frac{7}{4}, x = - 6

4 x^{\frac{3}{2}} - 13 x^{\frac{1}{2}} - 12 x^{- \frac{1}{2}}

2 x^{3} y^{2} z + 10 x^{2} y z^{3}

- \frac{1}{3} \cdot 2

\frac{5}{6} x - \frac{1}{4} x \geq \frac{7}{12} x + \frac{2}{3}

7 x^{2} - 2 x - 5

What are the solutions to the equation 4x^2+31x=-42 ?
The solutions to the equation 4x^2+31x=-42 are x=-7/4 ,x=-6
Find the zeros of 4x^2+31x=-42
The zeros of 4x^2+31x=-42 are x=-7/4 ,x=-6