What are the solutions to the equation 4x^2=80 ?

The solutions to the equation 4x^2=80 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of 4x^2=80

The zeros of 4x^2=80 are x=2sqrt(5),x=-2sqrt(5)

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4 x^{2} = 80

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

4 x^{2} = 80

Divide both sides by

4

x^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

3 a - b^{2} + 2 b^{2} x - 6 a x

\frac{2 ( k ^{4} ) ^{2}}{2 k ^{4}}

9 - x \leq - 11

∣ x - 1 ∣ = 8

2 x \leq 1

What are the solutions to the equation 4x^2=80 ?
The solutions to the equation 4x^2=80 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of 4x^2=80
The zeros of 4x^2=80 are x=2sqrt(5),x=-2sqrt(5)