What are the solutions to the equation 2n^2+5n+3=0 ?

The solutions to the equation 2n^2+5n+3=0 are n=-1,n=-3/2

Find the zeros of 2n^2+5n+3=0

The zeros of 2n^2+5n+3=0 are n=-1,n=-3/2

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2 n^{2} + 5 n + 3 = 0

n = - 1, n = - \frac{3}{2}

Decimal Notation

n = - 1, n = - 1.5

Solution steps

2 n^{2} + 5 n + 3 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

5^{2} - 4 \cdot 2 \cdot 3 = 1

n_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 5 + 1}{2 \cdot 2}, n_{2} = \frac{- 5 - 1}{2 \cdot 2}

n = \frac{- 5 + 1}{2 \cdot 2} : - 1

n = \frac{- 5 - 1}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

n = - 1, n = - \frac{3}{2}

lo g_{5} (\frac{1}{1000})

3 x + 8 = 5 x - 3 x

17 - 2 a \leq 29

\frac{2 x}{5} = \frac{3 x}{4} - 14

\frac{7 i}{8 + i}

What are the solutions to the equation 2n^2+5n+3=0 ?
The solutions to the equation 2n^2+5n+3=0 are n=-1,n=-3/2
Find the zeros of 2n^2+5n+3=0
The zeros of 2n^2+5n+3=0 are n=-1,n=-3/2