What are the solutions to the equation 3x^2-8x-16=0 ?

The solutions to the equation 3x^2-8x-16=0 are x=4,x=-4/3

Find the zeros of 3x^2-8x-16=0

The zeros of 3x^2-8x-16=0 are x=4,x=-4/3

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3 x^{2} - 8 x - 16 = 0

x = 4, x = - \frac{4}{3}

Decimal Notation

x = 4, x = - 1.33333 \dots

Solution steps

3 x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 16) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 3}

x = \frac{- ( - 8 ) + 16}{2 \cdot 3} : 4

x = \frac{- ( - 8 ) - 16}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{4}{3}

- 16 t^{2} + 32 t + 48

(4 x)^{\frac{5}{2}}

10 x^{2} - 4 x - 6

m^{2} - 4 m - 32

4 a + 10 > - 18

What are the solutions to the equation 3x^2-8x-16=0 ?
The solutions to the equation 3x^2-8x-16=0 are x=4,x=-4/3
Find the zeros of 3x^2-8x-16=0
The zeros of 3x^2-8x-16=0 are x=4,x=-4/3