What are the solutions to the equation -2x^2-5x=0 ?

The solutions to the equation -2x^2-5x=0 are x=-5/2 ,x=0

Find the zeros of -2x^2-5x=0

The zeros of -2x^2-5x=0 are x=-5/2 ,x=0

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- 2 x^{2} - 5 x = 0

x = - \frac{5}{2}, x = 0

Decimal Notation

x = - 2.5, x = 0

Solution steps

- 2 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 5)^{2} - 4 (- 2) \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 ( - 2 )}, x_{2} = \frac{- ( - 5 ) - 5}{2 ( - 2 )}

x = \frac{- ( - 5 ) + 5}{2 ( - 2 )} : - \frac{5}{2}

x = \frac{- ( - 5 ) - 5}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = 0

3 w + 3 (2 w - 10) \geq 10 w - 6 - 1

\frac{\frac{5}{2}}{\frac{3}{2}}

\frac{4}{3} x < - 8

16 + 2.4 = 22.5

4 x^{2} + 4 x - 80

What are the solutions to the equation -2x^2-5x=0 ?
The solutions to the equation -2x^2-5x=0 are x=-5/2 ,x=0
Find the zeros of -2x^2-5x=0
The zeros of -2x^2-5x=0 are x=-5/2 ,x=0