What are the solutions to the equation 6x^2+12x=-2 ?

The solutions to the equation 6x^2+12x=-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

Find the zeros of 6x^2+12x=-2

The zeros of 6x^2+12x=-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

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6 x^{2} + 12 x = - 2

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

Decimal Notation

x = - 0.18350 \dots, x = - 1.81649 \dots

Solution steps

6 x^{2} + 12 x = - 2

Move

2

to the left side

6 x^{2} + 12 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 \cdot 2 = 46

x_{1, 2} = \frac{- 12 \pm 4 6}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 4 6}{2 \cdot 6}, x_{2} = \frac{- 12 - 4 6}{2 \cdot 6}

x = \frac{- 12 + 4 6}{2 \cdot 6} : \frac{- 3 + 6}{3}

x = \frac{- 12 - 4 6}{2 \cdot 6} : - \frac{3 + 6}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

∣ w - 4 ∣ > 3

\frac{2}{x} \leq \frac{1}{x + 6}

∣ m + 5 ∣ + 9 \leq 30

- 5 x + 6 > - 4

13 = \frac{3}{4} (5 x + 8)

What are the solutions to the equation 6x^2+12x=-2 ?
The solutions to the equation 6x^2+12x=-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3
Find the zeros of 6x^2+12x=-2
The zeros of 6x^2+12x=-2 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3