What is 2sqrt(4r-3)>10 ?

The solution to 2sqrt(4r-3)>10 is r>7

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2sqrt(4r-3)>10

2 4 r - 3 > 10

r > 7

Interval Notation

(7, \infty)

Solution steps

2 4 r - 3 > 10

Divide both sides by

2

\frac{2 4 r - 3}{2} > \frac{10}{2}

Simplify

4 r - 3 > 5

Square both sides

(4 r - 3)^{2} > 5^{2}

Simplify

4 r - 3 > 25

4 r - 3 > 25 : r > 7

r > 7

Find singularity points

Find non-negative values for radicals:

r \geq \frac{3}{4}

Combine the intervals

r > 7 and r \geq \frac{3}{4}

Merge Overlapping Intervals

r > 7

\frac{5 x ^{5} y ^{7}}{x ^{8} y ^{3}}

2 x^{2} - 1 = 9 x

x^{2} = - 6 x + 7

x^{2} - 8 x = - 16

(p - q) (p - q)