What are the solutions to the equation 4x^2+7x=15 ?

The solutions to the equation 4x^2+7x=15 are x= 5/4 ,x=-3

Find the zeros of 4x^2+7x=15

The zeros of 4x^2+7x=15 are x= 5/4 ,x=-3

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4 x^{2} + 7 x = 15

x = \frac{5}{4}, x = - 3

Decimal Notation

x = 1.25, x = - 3

Solution steps

4 x^{2} + 7 x = 15

Move

15

to the left side

4 x^{2} + 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 15 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 15) = 17

x_{1, 2} = \frac{- 7 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 17}{2 \cdot 4}, x_{2} = \frac{- 7 - 17}{2 \cdot 4}

x = \frac{- 7 + 17}{2 \cdot 4} : \frac{5}{4}

x = \frac{- 7 - 17}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - 3

4 x - 2 = 6

2 x < - 6

\frac{z}{3} + 58 < 373

25 x^{2} - 30 x + 9

3 v^{2} + 17 v + 24 = 5

What are the solutions to the equation 4x^2+7x=15 ?
The solutions to the equation 4x^2+7x=15 are x= 5/4 ,x=-3
Find the zeros of 4x^2+7x=15
The zeros of 4x^2+7x=15 are x= 5/4 ,x=-3