What is (x-3)/(33)<(x-2)/(12) ?

The solution to (x-3)/(33) 10/7

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(x-3)/(33)<(x-2)/(12)

\frac{x - 3}{33} < \frac{x - 2}{12}

x > \frac{10}{7}

Interval Notation

(\frac{10}{7}, \infty)

Decimal Notation

x > 1.42857 \dots

Solution steps

\frac{x - 3}{33} < \frac{x - 2}{12}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(x - 3) \cdot 12 < 33 (x - 2)

Expand

(x - 3) \cdot 12 : 12 x - 36

Expand

33 (x - 2) : 33 x - 66

12 x - 36 < 33 x - 66

Move

36

to the right side

12 x < 33 x - 30

Move

33 x

to the left side

- 21 x < - 30

Multiply both sides by

- 1

21 x > 30

Divide both sides by

21

x > \frac{10}{7}

(x + 3) (x - 5) < 0

- 8 D + 5 + 5 D = 1 - 3 D - 5

- 10 n < 1 0^{2}

2 y^{2} = 0

\frac{10}{125}

What is (x-3)/(33)<(x-2)/(12) ?
The solution to (x-3)/(33)<(x-2)/(12) is x> 10/7