What are the solutions to the equation 5x^2+3x-9=0 ?

The solutions to the equation 5x^2+3x-9=0 are x=(-3+3sqrt(21))/(10),x=(-3-3sqrt(21))/(10)

Find the zeros of 5x^2+3x-9=0

The zeros of 5x^2+3x-9=0 are x=(-3+3sqrt(21))/(10),x=(-3-3sqrt(21))/(10)

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5 x^{2} + 3 x - 9 = 0

x = \frac{- 3 + 3 21}{10}, x = \frac{- 3 - 3 21}{10}

Decimal Notation

x = 1.07477 \dots, x = - 1.67477 \dots

Solution steps

5 x^{2} + 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 9) = 321

x_{1, 2} = \frac{- 3 \pm 3 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 3 21}{2 \cdot 5}, x_{2} = \frac{- 3 - 3 21}{2 \cdot 5}

x = \frac{- 3 + 3 21}{2 \cdot 5} : \frac{- 3 + 3 21}{10}

x = \frac{- 3 - 3 21}{2 \cdot 5} : \frac{- 3 - 3 21}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 3 21}{10}, x = \frac{- 3 - 3 21}{10}

72 + \frac{1}{4} 98

∣ 2 u + 5 ∣ \leq 7

\frac{5}{2} x + \frac{x - 4}{2} = 11

- \frac{4}{3} - 1

x^{2} + \frac{8}{7} + \frac{15}{49} = 0

What are the solutions to the equation 5x^2+3x-9=0 ?
The solutions to the equation 5x^2+3x-9=0 are x=(-3+3sqrt(21))/(10),x=(-3-3sqrt(21))/(10)
Find the zeros of 5x^2+3x-9=0
The zeros of 5x^2+3x-9=0 are x=(-3+3sqrt(21))/(10),x=(-3-3sqrt(21))/(10)