What are the solutions to the equation 5x^2-18x+16=0 ?

The solutions to the equation 5x^2-18x+16=0 are x=2,x= 8/5

Find the zeros of 5x^2-18x+16=0

The zeros of 5x^2-18x+16=0 are x=2,x= 8/5

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5 x^{2} - 18 x + 16 = 0

x = 2, x = \frac{8}{5}

Decimal Notation

x = 2, x = 1.6

Solution steps

5 x^{2} - 18 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 5 \cdot 16}{2 \cdot 5}

(- 18)^{2} - 4 \cdot 5 \cdot 16 = 2

x_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 5}, x_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 5}

x = \frac{- ( - 18 ) + 2}{2 \cdot 5} : 2

x = \frac{- ( - 18 ) - 2}{2 \cdot 5} : \frac{8}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{8}{5}

\frac{x - 3}{x + 5} > 0

\frac{3 x - 5}{x - 2} \geq \frac{4}{x + 1}

2 x^{2} - 2 x

3 (x + 3)^{2} = 0

\frac{x}{2} + \frac{3}{2} = \frac{x + 3}{6}

What are the solutions to the equation 5x^2-18x+16=0 ?
The solutions to the equation 5x^2-18x+16=0 are x=2,x= 8/5
Find the zeros of 5x^2-18x+16=0
The zeros of 5x^2-18x+16=0 are x=2,x= 8/5