What is 1<= 2|x+3|<= 5 ?

The solution to 1<= 2|x+3|<= 5 is -11/2 <= x<=-7/2 \lor-5/2 <= x<=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1<= 2|x+3|<= 5

1 \leq 2 ∣ x + 3 ∣ \leq 5

- \frac{11}{2} \leq x \leq - \frac{7}{2} or - \frac{5}{2} \leq x \leq - \frac{1}{2}

Interval Notation

[- \frac{11}{2}, - \frac{7}{2}] \cup [- \frac{5}{2}, - \frac{1}{2}]

Decimal Notation

- 5.5 \leq x \leq - 3.5 or - 2.5 \leq x \leq - 0.5

Solution steps

1 \leq 2 ∣ x + 3 ∣ \leq 5

a \leq u \leq b

then

a \leq u and u \leq b

1 \leq 2 ∣ x + 3 ∣ and 2 ∣ x + 3 ∣ \leq 5

1 \leq 2 ∣ x + 3 ∣ : x \leq - \frac{7}{2} or x \geq - \frac{5}{2}

2 ∣ x + 3 ∣ \leq 5 : - \frac{11}{2} \leq x \leq - \frac{1}{2}

Combine the intervals

(x \leq - \frac{7}{2} or x \geq - \frac{5}{2}) and - \frac{11}{2} \leq x \leq - \frac{1}{2}

Merge Overlapping Intervals

- \frac{11}{2} \leq x \leq - \frac{7}{2} or - \frac{5}{2} \leq x \leq - \frac{1}{2}

\frac{2}{7} + \frac{5}{14}

3 x^{3} - 13 x^{2} + 43 x - 13

\frac{y}{6} \leq 2

∣ x + 4 ∣ \geq 2

2 a^{2} + 5 a - 5 = 0

What is 1<= 2|x+3|<= 5 ?
The solution to 1<= 2|x+3|<= 5 is -11/2 <= x<=-7/2 \lor-5/2 <= x<=-1/2