What is the answer to \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)| ?

The answer to \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)| is x=(32sqrt(15)-121)/2

Solve for x: \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)|

The solution is x=(32sqrt(15)-121)/2

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x = \frac{32 15 - 121}{2}

Decimal Notation

x = 1.46773 \dots

Solution steps

Take both sides of the equation to the power of

4 : 3 - 2 x = 124 - 3215

3 - 2 x = 124 - 3215

Solve

3 - 2 x = 124 - 3215 : x = \frac{32 15 - 121}{2}

x = \frac{32 15 - 121}{2}

Verify Solutions:

x = \frac{32 15 - 121}{2}

True

The solution is

x = \frac{32 15 - 121}{2}

6 x + 3 = 21

3 \cdot \frac{8}{3}

4 (x - 5)^{2} - 2 = 26

(x^{\frac{2}{3}})^{3}

8 q^{2} - 10 q + 3 = 0

What is the answer to \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)| ?
The answer to \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)| is x=(32sqrt(15)-121)/2
Solve for x: \sqrt[4]{3-2x}=|sqrt(3)-sqrt(5)|
The solution is x=(32sqrt(15)-121)/2