What are the solutions to the equation 8x^2=4x ?

The solutions to the equation 8x^2=4x are x=0,x= 1/2

Find the zeros of 8x^2=4x

The zeros of 8x^2=4x are x=0,x= 1/2

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8 x^{2} = 4 x

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

8 x^{2} = 4 x

Move

4 x

to the left side

8 x^{2} - 4 x = 0

Factor

8 x^{2} - 4 x : 4 x (2 x - 1)

4 x (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x - 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

\frac{π}{2} - \frac{π}{5}

3 x + 15 - 9 = 2 (x + 2)

\frac{3 x - 1}{5} - \frac{x - 2}{2} = x + 4

\frac{3 x}{4} = 9

2^{6}

What are the solutions to the equation 8x^2=4x ?
The solutions to the equation 8x^2=4x are x=0,x= 1/2
Find the zeros of 8x^2=4x
The zeros of 8x^2=4x are x=0,x= 1/2