What are the solutions to the equation 5x^2+9x-2=0 ?

The solutions to the equation 5x^2+9x-2=0 are x= 1/5 ,x=-2

Find the zeros of 5x^2+9x-2=0

The zeros of 5x^2+9x-2=0 are x= 1/5 ,x=-2

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5 x^{2} + 9 x - 2 = 0

x = \frac{1}{5}, x = - 2

Decimal Notation

x = 0.2, x = - 2

Solution steps

5 x^{2} + 9 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

9^{2} - 4 \cdot 5 (- 2) = 11

x_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 9 + 11}{2 \cdot 5}, x_{2} = \frac{- 9 - 11}{2 \cdot 5}

x = \frac{- 9 + 11}{2 \cdot 5} : \frac{1}{5}

x = \frac{- 9 - 11}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - 2

5 (x - 4) + 2 = - 173

∣ y - 1 ∣ = 1 - y

8 x^{2} = 4 x

\frac{π}{2} - \frac{π}{5}

3 x + 15 - 9 = 2 (x + 2)

What are the solutions to the equation 5x^2+9x-2=0 ?
The solutions to the equation 5x^2+9x-2=0 are x= 1/5 ,x=-2
Find the zeros of 5x^2+9x-2=0
The zeros of 5x^2+9x-2=0 are x= 1/5 ,x=-2