What are the solutions to the equation 5(4-x)^2=4(5-x)^2 ?

The solutions to the equation 5(4-x)^2=4(5-x)^2 are x=2sqrt(5),x=-2sqrt(5)

Find the zeros of 5(4-x)^2=4(5-x)^2

The zeros of 5(4-x)^2=4(5-x)^2 are x=2sqrt(5),x=-2sqrt(5)

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5 (4 - x)^{2} = 4 (5 - x)^{2}

x = 25, x = - 25

Decimal Notation

x = 4.47213 \dots, x = - 4.47213 \dots

Solution steps

5 (4 - x)^{2} = 4 (5 - x)^{2}

Expand

5 (4 - x)^{2} : 80 - 40 x + 5 x^{2}

Expand

4 (5 - x)^{2} : 100 - 40 x + 4 x^{2}

80 - 40 x + 5 x^{2} = 100 - 40 x + 4 x^{2}

Move

80

to the right side

- 40 x + 5 x^{2} = 4 x^{2} - 40 x + 20

Move

40 x

to the left side

5 x^{2} = 4 x^{2} + 20

Move

4 x^{2}

to the left side

x^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 20, x = - 20

20 = 25

- 20 = - 25

x = 25, x = - 25

f (\frac{1}{x} + \frac{1}{h}) - (\frac{1}{x})

3 (1 - 2 x) + 12 = 10 - 2 (x - 3)

(1 + \frac{0.09}{12})^{12} - 1

\frac{y}{2} - 5 \leq 7

58 x + 52 = 78 x - 78

What are the solutions to the equation 5(4-x)^2=4(5-x)^2 ?
The solutions to the equation 5(4-x)^2=4(5-x)^2 are x=2sqrt(5),x=-2sqrt(5)
Find the zeros of 5(4-x)^2=4(5-x)^2
The zeros of 5(4-x)^2=4(5-x)^2 are x=2sqrt(5),x=-2sqrt(5)