What are the solutions to the equation 10n^2-n-20610=0 ?

The solutions to the equation 10n^2-n-20610=0 are n=(1+sqrt(824401))/(20),n=(1-sqrt(824401))/(20)

Find the zeros of 10n^2-n-20610=0

The zeros of 10n^2-n-20610=0 are n=(1+sqrt(824401))/(20),n=(1-sqrt(824401))/(20)

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10 n^{2} - n - 20610 = 0

n = \frac{1 + 824401}{20}, n = \frac{1 - 824401}{20}

Decimal Notation

n = 45.44826 \dots, n = - 45.34826 \dots

Solution steps

10 n^{2} - n - 20610 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 10 ( - 20610 )}{2 \cdot 10}

(- 1)^{2} - 4 \cdot 10 (- 20610) = 824401

n_{1, 2} = \frac{- ( - 1 ) \pm 824401}{2 \cdot 10}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 824401}{2 \cdot 10}, n_{2} = \frac{- ( - 1 ) - 824401}{2 \cdot 10}

n = \frac{- ( - 1 ) + 824401}{2 \cdot 10} : \frac{1 + 824401}{20}

n = \frac{- ( - 1 ) - 824401}{2 \cdot 10} : \frac{1 - 824401}{20}

The solutions to the quadratic equation are:

n = \frac{1 + 824401}{20}, n = \frac{1 - 824401}{20}

x^{2} + 10 = 0

(x + 1) (x + 1) = x - 1 (5 x + x - 1)

\frac{40}{5}

2 x^{2} - 6 x + 8 = 0

\frac{( x - 8 )}{25} + \frac{( x - 17 )}{140} + \frac{x}{10} = 0

What are the solutions to the equation 10n^2-n-20610=0 ?
The solutions to the equation 10n^2-n-20610=0 are n=(1+sqrt(824401))/(20),n=(1-sqrt(824401))/(20)
Find the zeros of 10n^2-n-20610=0
The zeros of 10n^2-n-20610=0 are n=(1+sqrt(824401))/(20),n=(1-sqrt(824401))/(20)