What are the solutions to the equation 4x^2=9x+9 ?

The solutions to the equation 4x^2=9x+9 are x=3,x=-3/4

Find the zeros of 4x^2=9x+9

The zeros of 4x^2=9x+9 are x=3,x=-3/4

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4 x^{2} = 9 x + 9

x = 3, x = - \frac{3}{4}

Decimal Notation

x = 3, x = - 0.75

Solution steps

4 x^{2} = 9 x + 9

Move

9

to the left side

4 x^{2} - 9 = 9 x

Move

9 x

to the left side

4 x^{2} - 9 - 9 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 9 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 (- 9) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 4}

x = \frac{- ( - 9 ) + 15}{2 \cdot 4} : 3

x = \frac{- ( - 9 ) - 15}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{3}{4}

- 11 k - 12 + 15 - 19 k

2 (- 6)^{2}

x^{3} + 5 x^{2} + 2 x + 10

2 (x - 2) = - 4

\frac{175 - 7 k ^{2}}{k ^{2} + 7 k - 60}

What are the solutions to the equation 4x^2=9x+9 ?
The solutions to the equation 4x^2=9x+9 are x=3,x=-3/4
Find the zeros of 4x^2=9x+9
The zeros of 4x^2=9x+9 are x=3,x=-3/4