What are the solutions to the equation x^2+8x+26=0 ?

The solutions to the equation x^2+8x+26=0 are x=-4+sqrt(10)i,x=-4-sqrt(10)i

Find the zeros of x^2+8x+26=0

The zeros of x^2+8x+26=0 are x=-4+sqrt(10)i,x=-4-sqrt(10)i

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x^{2} + 8 x + 26 = 0

x = - 4 + 10 i, x = - 4 - 10 i

Solution steps

x^{2} + 8 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 26 : 210 i

x_{1, 2} = \frac{- 8 \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 10 i}{2 \cdot 1}

x = \frac{- 8 + 2 10 i}{2 \cdot 1} : - 4 + 10 i

x = \frac{- 8 - 2 10 i}{2 \cdot 1} : - 4 - 10 i

The solutions to the quadratic equation are:

x = - 4 + 10 i, x = - 4 - 10 i

5 x^{2} = 15 x

(- 18 m^{2})^{2} - 4 (1 + m^{2}) (81 m^{2} - 49) = 0

p^{2} + p - 2 = 0

x^{4} - 8 x^{2} + 7

- 14 x + 3 = - 9 x - 12

What are the solutions to the equation x^2+8x+26=0 ?
The solutions to the equation x^2+8x+26=0 are x=-4+sqrt(10)i,x=-4-sqrt(10)i
Find the zeros of x^2+8x+26=0
The zeros of x^2+8x+26=0 are x=-4+sqrt(10)i,x=-4-sqrt(10)i