What are the solutions to the equation -2x^2+5x=0 ?

The solutions to the equation -2x^2+5x=0 are x=0,x= 5/2

Find the zeros of -2x^2+5x=0

The zeros of -2x^2+5x=0 are x=0,x= 5/2

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- 2 x^{2} + 5 x = 0

x = 0, x = \frac{5}{2}

Decimal Notation

x = 0, x = 2.5

Solution steps

- 2 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

5^{2} - 4 (- 2) \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 ( - 2 )}, x_{2} = \frac{- 5 - 5}{2 ( - 2 )}

x = \frac{- 5 + 5}{2 ( - 2 )} : 0

x = \frac{- 5 - 5}{2 ( - 2 )} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{2}

3 x + 5 x + 4 - x + 7 = 8

- \frac{12}{2}

4 (43) + 38 = 180

\frac{( - 9 + x )}{2} = - 9

x^{2} + x^{2} = 1 0^{2}

What are the solutions to the equation -2x^2+5x=0 ?
The solutions to the equation -2x^2+5x=0 are x=0,x= 5/2
Find the zeros of -2x^2+5x=0
The zeros of -2x^2+5x=0 are x=0,x= 5/2