What are the solutions to the equation 2x^2+x-10=0 ?

The solutions to the equation 2x^2+x-10=0 are x=2,x=-5/2

Find the zeros of 2x^2+x-10=0

The zeros of 2x^2+x-10=0 are x=2,x=-5/2

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2 x^{2} + x - 10 = 0

x = 2, x = - \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5

Solution steps

2 x^{2} + x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 10) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 2}, x_{2} = \frac{- 1 - 9}{2 \cdot 2}

x = \frac{- 1 + 9}{2 \cdot 2} : 2

x = \frac{- 1 - 9}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{5}{2}

- 500

∣ x - 6 ∣ > 2

1.8 \cdot 1 0^{- 5} = \frac{x ^{2}}{( 0.1 )}

141 - 8 x = 10 x - 21

9 \cdot \frac{1}{3}

What are the solutions to the equation 2x^2+x-10=0 ?
The solutions to the equation 2x^2+x-10=0 are x=2,x=-5/2
Find the zeros of 2x^2+x-10=0
The zeros of 2x^2+x-10=0 are x=2,x=-5/2