What are the solutions to the equation (3x+2)^2=9 ?

The solutions to the equation (3x+2)^2=9 are x= 1/3 ,x=-5/3

Find the zeros of (3x+2)^2=9

The zeros of (3x+2)^2=9 are x= 1/3 ,x=-5/3

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(3 x + 2)^{2} = 9

x = \frac{1}{3}, x = - \frac{5}{3}

Decimal Notation

x = 0.33333 \dots, x = - 1.66666 \dots

Solution steps

(3 x + 2)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 9 : x = \frac{1}{3}

Solve

3 x + 2 = - 9 : x = - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - \frac{5}{3}

\frac{3}{5} + \frac{7}{2}

\frac{2}{3} > \frac{5}{6}

(3 y^{2}) (4 y^{5})

- 17 < 4 b + 3 \leq - 1

\frac{d y}{d t} - y = \frac{t}{y}

What are the solutions to the equation (3x+2)^2=9 ?
The solutions to the equation (3x+2)^2=9 are x= 1/3 ,x=-5/3
Find the zeros of (3x+2)^2=9
The zeros of (3x+2)^2=9 are x= 1/3 ,x=-5/3