What are the solutions to the equation (y+2)^2+8=14 ?

The solutions to the equation (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2

Find the zeros of (y+2)^2+8=14

The zeros of (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2

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(y + 2)^{2} + 8 = 14

y = 6 - 2, y = - 6 - 2

Decimal Notation

y = 0.44948 \dots, y = - 4.44948 \dots

Solution steps

(y + 2)^{2} + 8 = 14

Move

8

to the right side

(y + 2)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 2 = 6 : y = 6 - 2

Solve

y + 2 = - 6 : y = - 6 - 2

The solutions to the quadratic equation are:

y = 6 - 2, y = - 6 - 2

y^{2} - 4 y + 4

- 4 x \leq 36

6 x + 5 x - 4 = 2 x - 8

5 - 2 m = 3

- 6 x > 15

What are the solutions to the equation (y+2)^2+8=14 ?
The solutions to the equation (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2
Find the zeros of (y+2)^2+8=14
The zeros of (y+2)^2+8=14 are y=sqrt(6)-2,y=-sqrt(6)-2