What are the solutions to the equation (3x-4)^2=39 ?

The solutions to the equation (3x-4)^2=39 are x=(sqrt(39)+4)/3 ,x=(-sqrt(39)+4)/3

Find the zeros of (3x-4)^2=39

The zeros of (3x-4)^2=39 are x=(sqrt(39)+4)/3 ,x=(-sqrt(39)+4)/3

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(3 x - 4)^{2} = 39

x = \frac{39 + 4}{3}, x = \frac{- 39 + 4}{3}

Decimal Notation

x = 3.41499 \dots, x = - 0.74833 \dots

Solution steps

(3 x - 4)^{2} = 39

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 39 : x = \frac{39 + 4}{3}

Solve

3 x - 4 = - 39 : x = \frac{- 39 + 4}{3}

The solutions to the quadratic equation are:

x = \frac{39 + 4}{3}, x = \frac{- 39 + 4}{3}

10 y^{2} - y - 93 = 0

a^{9} - b^{3}

5 \cdot \frac{3}{5}

\frac{4 ^{2}}{- 5}

What are the solutions to the equation (3x-4)^2=39 ?
The solutions to the equation (3x-4)^2=39 are x=(sqrt(39)+4)/3 ,x=(-sqrt(39)+4)/3
Find the zeros of (3x-4)^2=39
The zeros of (3x-4)^2=39 are x=(sqrt(39)+4)/3 ,x=(-sqrt(39)+4)/3