What are the solutions to the equation 4x^2+3x=7x+3 ?

The solutions to the equation 4x^2+3x=7x+3 are x= 3/2 ,x=-1/2

Find the zeros of 4x^2+3x=7x+3

The zeros of 4x^2+3x=7x+3 are x= 3/2 ,x=-1/2

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4 x^{2} + 3 x = 7 x + 3

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

4 x^{2} + 3 x = 7 x + 3

Move

3

to the left side

4 x^{2} + 3 x - 3 = 7 x

Move

7 x

to the left side

4 x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

x = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

- 2 x + 3 = 2 x + 3

∣ d + 1 ∣ = 7

8 x^{5} - 98 x^{3}

2 a^{2} x - 5 a^{2} y + 15 b y - 6 b x

- 8 x + 3 = - 29

What are the solutions to the equation 4x^2+3x=7x+3 ?
The solutions to the equation 4x^2+3x=7x+3 are x= 3/2 ,x=-1/2
Find the zeros of 4x^2+3x=7x+3
The zeros of 4x^2+3x=7x+3 are x= 3/2 ,x=-1/2