What are the solutions to the equation 2x^2-11x-2=0 ?

The solutions to the equation 2x^2-11x-2=0 are x=(11+sqrt(137))/4 ,x=(11-sqrt(137))/4

Find the zeros of 2x^2-11x-2=0

The zeros of 2x^2-11x-2=0 are x=(11+sqrt(137))/4 ,x=(11-sqrt(137))/4

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2 x^{2} - 11 x - 2 = 0

x = \frac{11 + 137}{4}, x = \frac{11 - 137}{4}

Decimal Notation

x = 5.67617 \dots, x = - 0.17617 \dots

Solution steps

2 x^{2} - 11 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 2 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 2) = 137

x_{1, 2} = \frac{- ( - 11 ) \pm 137}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 137}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 137}{2 \cdot 2}

x = \frac{- ( - 11 ) + 137}{2 \cdot 2} : \frac{11 + 137}{4}

x = \frac{- ( - 11 ) - 137}{2 \cdot 2} : \frac{11 - 137}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 137}{4}, x = \frac{11 - 137}{4}

2 k^{2} + 22 k = 74

x + 11 = \frac{( x - 13 ) ^{2}}{2}

x^{2} + 6 x - 60 = 3 x - 20

2 7^{- \frac{2}{3}}

x^{2} \cdot y^{2}

What are the solutions to the equation 2x^2-11x-2=0 ?
The solutions to the equation 2x^2-11x-2=0 are x=(11+sqrt(137))/4 ,x=(11-sqrt(137))/4
Find the zeros of 2x^2-11x-2=0
The zeros of 2x^2-11x-2=0 are x=(11+sqrt(137))/4 ,x=(11-sqrt(137))/4