What are the solutions to the equation (2x-87)(x+5)=0 ?

The solutions to the equation (2x-87)(x+5)=0 are x= 87/2 ,x=-5

Find the zeros of (2x-87)(x+5)=0

The zeros of (2x-87)(x+5)=0 are x= 87/2 ,x=-5

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(2 x - 87) (x + 5) = 0

x = \frac{87}{2}, x = - 5

Decimal Notation

x = 43.5, x = - 5

Solution steps

(2 x - 87) (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 87 = 0 or x + 5 = 0

Solve

2 x - 87 = 0 : x = \frac{87}{2}

Solve

x + 5 = 0 : x = - 5

The solutions to the quadratic equation are:

x = \frac{87}{2}, x = - 5

8 x - 3 = - 19

∣ x + 3 ∣ = 0

4 x - 12 = 24

\frac{x}{x + 4} > 0

- 2 j + 7 = - 12

What are the solutions to the equation (2x-87)(x+5)=0 ?
The solutions to the equation (2x-87)(x+5)=0 are x= 87/2 ,x=-5
Find the zeros of (2x-87)(x+5)=0
The zeros of (2x-87)(x+5)=0 are x= 87/2 ,x=-5