What are the solutions to the equation 9x^2-6x+2=0 ?

The solutions to the equation 9x^2-6x+2=0 are x= 1/3+i 1/3 ,x= 1/3-i 1/3

Find the zeros of 9x^2-6x+2=0

The zeros of 9x^2-6x+2=0 are x= 1/3+i 1/3 ,x= 1/3-i 1/3

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9 x^{2} - 6 x + 2 = 0

x = \frac{1}{3} + i \frac{1}{3}, x = \frac{1}{3} - i \frac{1}{3}

Solution steps

9 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

(- 6)^{2} - 4 \cdot 9 \cdot 2 : 6 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 9}

x = \frac{- ( - 6 ) + 6 i}{2 \cdot 9} : \frac{1}{3} + i \frac{1}{3}

x = \frac{- ( - 6 ) - 6 i}{2 \cdot 9} : \frac{1}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} + i \frac{1}{3}, x = \frac{1}{3} - i \frac{1}{3}

100 x^{2} - 81

\frac{5 π}{12} - π

∣ x - 4 ∣ \leq - 3

5 ∣ x + 1 ∣ + 9 > 8

\frac{x ^{4}}{y ^{- 6}}

What are the solutions to the equation 9x^2-6x+2=0 ?
The solutions to the equation 9x^2-6x+2=0 are x= 1/3+i 1/3 ,x= 1/3-i 1/3
Find the zeros of 9x^2-6x+2=0
The zeros of 9x^2-6x+2=0 are x= 1/3+i 1/3 ,x= 1/3-i 1/3